Answer to 4.2.14 (a) :
Substitute 1-x = t. Then dx=-dt . Now the substituted integrand should look like this :
Saturday 27 August 2016
Answer to 4.2.14 all subparts
The answer given for some of the sub question in the book have some mistakes. I'm posting the corrected solution here.
The solution given in the book for this question is incorrect. You can solve the question as follows.
Substitute 1-x = t. Then dx=-dt . Now the substituted integrand should look like this :
Now, integrating term by term, we'll get :
Taking out the common term, we get :
Now replacing t with 1-x, you'll get the answer as :
This should be the answer. The answer given on the book has a mistake.
Substitute 1-x = t. Then dx=-dt . Now the substituted integrand should look like this :
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